Diamond of death and Scope resolution operator (c++)

Question

I have this code (diamond problem):

#include 
using namespace std;

struct Top
{
    void print() { cout << \"Top::print()\" << e         


        

Answer 1

Actually, giving code is working fine as I tried it on Visual Studio 2019. There are two way to solve Diamond Problem; - Using Scope resolution operator - Inherit base class as virtual

Calling print function by b.Right::Top::print() should be executed with no errors. But there is still two objects of your base class (Top) referred from your Bottom class.

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