format '%s' expects argument of type 'char *'

Question

#include 
int main(void)
{
    int i,j,k;
    char st;
    printf(\"enter string\\n\");
    scanf(\"%s\", st);         


        

Answer 1

As others have mentioned you want to create an array:

Change char st; to char st[10]; or whatever size array you want.

With the above change st is an array that has 10 individual elements that can hold a single char value.