format '%s' expects argument of type 'char *'

Question

#include 
int main(void)
{
    int i,j,k;
    char st;
    printf(\"enter string\\n\");
    scanf(\"%s\", st);         


        

Answer 1

st is type of char &st is type of char * Take care of the difference. BTW, only one char cannot be used to store a string. Use char[] array.