format '%s' expects argument of type 'char *'

Question

#include 
int main(void)
{
    int i,j,k;
    char st;
    printf(\"enter string\\n\");
    scanf(\"%s\", st);         


        

Answer 1

scanf needs a pointer to char* to indicate you are scanning a string.

You are supplying a character that's allocated on the stack.

You either want to use a getchar() or make st a char array.