format '%s' expects argument of type 'char *'

Question

#include 
int main(void)
{
    int i,j,k;
    char st;
    printf(\"enter string\\n\");
    scanf(\"%s\", st);         


        

Answer 1

char st is a single character. Judging by the rest of your code, you probably intended to declare an array of characters:

char st[80];