random.choice() returns same value at the same second, how does one avoid it?

Question

I have been looking at similar questions regarding how to generate random numbers in python. Example: Similar Question - but i do not have the problem that the randomfunctio

Answer 1

def getRandomID(n):

    import datetime
    import random

    random.seed(datetime.datetime.now())

    letters = "abcdefghiklmnopqrstuvwwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890"

    idList = [ ''.join([random.choice(letters) for j in range(1,36)]) for i in range(n)]

    return idList

this script in the 3rd test of 10 million ids again have made them all unique

changing for loop to list comprehension did speedup quite a bit.

>>> listt = getRandomID(10000000)
>>> print(len(listt))
10000000

>>> setOfIds = set(listt)
>>> print(len(setOfIds))
10000000

this script uses permutations with repetition: 62 choose 35, to theoretically total number of ids is quite big it is pow(62,35)

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