Convert floating point variable to integer?

Question

The shell script shown below will show a warning if the page takes more than 6 seconds to load. The problem is that the myduration variable is not an integer. H

Answer 1

It's not entirely clear, but I think you're asking how to convert a floating-point value (myduration) to an integer in bash. Something like this may help you, depending on which way you want to round your number.

#!/bin/bash

floor_val=
ceil_val=

function floor() {
    float_in=$1
    floor_val=${float_in/.*}
}

function ceiling() {
    float_in=$1
    ceil_val=${float_in/.*}
    ceil_val=$((ceil_val+1))
}


float_val=$1
echo Passed in: $float_val
floor $float_val
ceiling $float_val

echo Result of floor: $floor_val
echo Result of ceiling: $ceil_val

Example usage:

$ ./int.sh 12.345
Passed in: 12.345
Result of floor: 12
Result of ceiling: 13