Best way to represent a readline loop in Scala?

Question

Coming from a C/C++ background, I\'m not very familiar with the functional style of programming so all my code tends to be very imperative, as in most cases I just can\'t se

Answer 1

Well, in Scala you can actually say:

val lines = scala.io.Source.fromFile("file.txt").mkString

But this is just a library sugar. See Read entire file in Scala? for other possiblities. What you are actually asking is how to apply functional paradigm to this problem. Here is a hint:

Source.fromFile("file.txt").getLines().foreach {println}

Do you get the idea behind this? foreach line in the file execute println function. BTW don't worry, getLines() returns an iterator, not the whole file. Now something more serious:

lines filter {_.startsWith("ab")} map {_.toUpperCase} foreach {println}

See the idea? Take lines (it can be an array, list, set, iterator, whatever that can be filtered and which contains an items having startsWith method) and filter taking only the items starting with "ab". Now take every item and map it by applying toUpperCase method. Finally foreach resulting item print it.

The last thought: you are not limited to a single type. For instance say you have a file containing integer number, one per line. If you want to read that file, parse the number and sum them up, simply say:

lines.map(_.toInt).sum