number of digits in a hex escape code in C/C++

Question

I\'m having a dispute with a colleague of mine. She says that the following:

char* a = \"\\x000aaxz\";

will/can be seen by the compiler as

Answer 1

well, for that matter, hex escape sequence ends at a non hex character, e.g \x0abc9k is 0abc9 in hex and then 'k' so in order to end a hex sequence, you will have to use double quotes twice at the end of it e.g. \x0ab""c9k , which takes only 0ab as hex

or alternately you could use octal escape sequence as there is limit to the numbers in octal escape sequence so there be maximum only three octal digits in it.. e.g. \o1234 is 123 in octal and then '4'

So, yes, she is right.