Can I use Python 3 super() in Python 2.5.6?

Question

Can I use clean Python 3 super() syntax in Python 2.5.6?
Maybe with some kind of __future__ import?

Answer 1

Note This is a terrible "solution", I post it only to make sure you don't do this at home!
I repeat: do not do this

One may think about using this mixin

class Super(object):
    def super(self):
        return super(self.__class__, self)

to obtain a self.super():

class A(object, Super):
    def __init__(self):
        print "A"

class B(A):
    def __init__(self):
        print "B"
        self.super().__init__()

yielding:

 >>> a = A()
 A
 >>> b = B()
 B
 A

But beware: This self.super() is not equivalent to super(B, self) - if A also called self.super().__init__(), the construction of a B would cause the A constructor to call itself indefinitely, since self.__class__ will remain B. This is due to the lack of the __class__ mentioned in the accepted answer. You can possibly work around this issue with a hidden state machine or a sophisticated metaclass that e.g. checks the actual class's position in self.__class__.mro(), but is it really worth it? Probably not...