Is it possible to use #define inside a function?

Question

For example, I saw source code like the following. Can we use #define in a function? How does it work? (more information: this code is what I copied from

Answer 1

Sure this is possible. The #define is processed by the preprocessor before the compiler does anything. It is a simple text replacement. The preprocessor doesn't even know if the line of code is inside or outside a function, class or whatever.

By the way, it is generally considered bad style to define preprocessor macros in C++. Most of the things they are used for can be better achieved with templates.