Generation of the same sequence of random numbers

Question

I want to generate random numbers in java, I know I should use existing methods like Math.random(), however, my question is: how can I generate the same sequence of numbers,

Answer 1

An example of using the same seed repeatedly.

public static void main(String... args) throws IOException {
    printDoublesForSeed(1);
    printDoublesForSeed(128);
    printDoublesForSeed(1);
    printDoublesForSeed(128);
}

private static void printDoublesForSeed(long seed) {
    double[] doubles = new double[10];
    Random rand = new Random(seed);
    for (int j = 0; j < doubles.length; j++) {
        doubles[j] = (long) (rand.nextDouble() * 100) / 100.0;
    }
    System.out.println("doubles with seed " + seed + " " + Arrays.toString(doubles));
}

prints

doubles with seed 1 [0.73, 0.41, 0.2, 0.33, 0.96, 0.0, 0.96, 0.93, 0.94, 0.93]
doubles with seed 128 [0.74, 0.53, 0.63, 0.41, 0.21, 0.2, 0.33, 0.74, 0.17, 0.47]
doubles with seed 1 [0.73, 0.41, 0.2, 0.33, 0.96, 0.0, 0.96, 0.93, 0.94, 0.93]
doubles with seed 128 [0.74, 0.53, 0.63, 0.41, 0.21, 0.2, 0.33, 0.74, 0.17, 0.47]

---

EDIT An interesting abuse of random seeds.

public static void main(String ... args) {
    System.out.println(randomString(-6225973)+' '+randomString(1598025));
}

public static String randomString(int seed) {
    Random rand = new Random(seed);
    StringBuilder sb = new StringBuilder();
    for(int i=0;i<5;i++)
        sb.append((char) ('a' + rand.nextInt(26)));
    return sb.toString();
}

prints

hello world