address of c++ template function

Question

Why does this fail to compile? (g++-4.5)

template < typename U >
static void h () {
}

int main () {
  auto p = &h; // error: p has inco         


        

Answer 1

It does not compile because type of 'p' is not known to the compiler which is a must in C++ unlike some other languages.

Try

template < typename U > 
static void h () { 
} 

int main () { 
  auto void (*p)() = &h; 
}