Round with integer division

Question

Is there is a simple, pythonic way of rounding to the nearest whole number without using floating point? I\'d like to do the following but with integer arithmetic:

Answer 1

skip = (((total << 1) // surplus) + 1) >> 1

Shifting things left by one bit effectively multiplies by two, shifting things right by one bit divides by two rounding down. Adding one in the middle makes it so that "rounding down" is actually rounding up if the result would have been above a .5 decimal part.

It's basically the same as if you wrote...

skip = int((1.0*total/surplus) + 0.5)

except with everything multplied by 2, and then later divided by 2, which is something you can do with integer arithmetic (since bit shifts don't require floating point).