How to open a PopupMenuButton?

Question

How do I open a popup menu from a second widget?

final button = new PopupMenuButton(
    itemBuilder: (_) => >[
                 


        

Answer 1

This works, but is inelegant (and has the same display problem as Rainer's solution above:

class _MyHomePageState extends State {
  final GlobalKey _menuKey = new GlobalKey();

  @override
  Widget build(BuildContext context) {
    final button = new PopupMenuButton(
        key: _menuKey,
        itemBuilder: (_) => >[
              new PopupMenuItem(
                  child: const Text('Doge'), value: 'Doge'),
              new PopupMenuItem(
                  child: const Text('Lion'), value: 'Lion'),
            ],
        onSelected: (_) {});

    final tile =
        new ListTile(title: new Text('Doge or lion?'), trailing: button, onTap: () {
          // This is a hack because _PopupMenuButtonState is private.
          dynamic state = _menuKey.currentState;
          state.showButtonMenu();
        });
    return new Scaffold(
      body: new Center(
        child: tile,
      ),
    );
  }
}

I suspect what you're actually asking for is something like what is tracked by https://github.com/flutter/flutter/issues/254 or https://github.com/flutter/flutter/issues/8277 -- the ability to associated a label with a control and have the label be clickable -- and is a missing feature from the Flutter framework.