Why a programmer would prefer O(N^3) instead of O(N^2)

Question

I was studying for my final exam and there is a question in the archive that I cannot find its answer:

The order-of-growth of the running time of one

Answer 1

Probably the #1 reason: because the O(N²) algorithm has enough higher constants that for the size of task being contemplated, the O(N³) version is faster.