How to get a JsonProcessingException using Jackson

Question

Might be a strange question but indeed I would like to achieve a a bit more coverage on my tests and although I coded against a JsonProcessingException I can\'t

Answer 1

You could use something like this:

private static class ClassThatJacksonCannotSerialize {
    private final ClassThatJacksonCannotSerialize self = this;

    @Override
    public String toString() {
        return self.getClass().getName();
   }
}

Which results in a JsonProcessingException with message Direct self-reference leading to cycle (through reference chain: ClassThatJacksonCannotSerialize["self"])