regex in bash expression

Question

I have 2 questions about regex in bash expression.

1.non-greedy mode

local temp_input=\'\"a1b\", \"d\" , \"45\"\'
if [[ $temp_input =~ \\\".*?\\\         


        

Answer 1

This is my first post, and I am very amateur at bash, so apologies if I haven't understood the question, but I wrote a function for non-greedy regex using entirely bash:

regex_non_greedy () {
    local string="$1"
    local regex="$2"
    local replace="$3"

    while [[ $string =~ $regex ]]; do
        local search=${BASH_REMATCH}
        string=${string/$search/$replace}
    done

    printf "%s" "$string"
}

Example invocation:

regex_non_greedy "all cats are grey and green" "gre+." "white"

Which returns:

all cats are white and white