Delete row in Google Sheets if certain “word” is found in cell

Question

I have a Google Sheet with over 3000 rows. Some of the rows contain words that are not relevant..So I need a way to delete these in bulk. For example, cells will contain som

Answer 1

Using the indexOf trick, I've managed to get the desired effect by changing...

This:

    if (row[1] == 'old')

To This:

    if (row[1].indexOf("old") > -1)

What's happening here:

The 'indexOf' goes in and finds the position of the first occurrence of the word "old", then returns back a number length value. If it doesn't find the word, the result will be -1. So, as long as you specify greater than "> -1", it will be true..and you'll be good!

Here's the complete code if anyone else needs this in the future,

/**
 * Deletes rows in the active spreadsheet that contain 'word' in column B
 * For more information on using the Spreadsheet API, see
 * https://developers.google.com/apps-script/service_spreadsheet
 */

function readRows() {
 var sheet = SpreadsheetApp.getActiveSheet();
 var rows = sheet.getDataRange();
 var numRows = rows.getNumRows();
 var values = rows.getValues();

 var rowsDeleted = 0;
 for (var i = 0; i <= numRows - 1; i++) {

 var row = values[i];

 if (row[1].indexOf("old") > -1) {
 sheet.deleteRow((parseInt(i)+1) - rowsDeleted);
 rowsDeleted++;
 }

 }
};


/**
 * Adds a custom menu to the active spreadsheet, containing a single menu item
 * for invoking the readRows() function specified above.
 * The onOpen() function, when defined, is automatically invoked whenever the
 * spreadsheet is opened.
 * For more information on using the Spreadsheet API, see
 * https://developers.google.com/apps-script/service_spreadsheet
 */
function onOpen() {
 var sheet = SpreadsheetApp.getActiveSpreadsheet();
 var entries = [{
 name : "Remove rows where column B is 'old'",
 functionName : "readRows"
 }];
 sheet.addMenu("Remove Rows", entries);
};