Bash: remove numbers at the end of names.

Question

I have files like: alien-skull-2224154.jpg snow-birds-red-arrows-thunderbirds-blue-angels-43264.jpg dead-space-album-1053.jpg

How can I remove in bash the \"ID\" s

Answer 1

Here's one way using bash parameter substitution:

for i in *.jpg; do mv "$i" "${i%-*}.jpg"; done

Or for the more general case (i.e. if you have other file extensions), try:

for i in *.*; do mv "$i" "${i%-*}.${i##*.}"; done

Results:

alien-skull.jpg
dead-space-album.jpg
snow-birds-red-arrows-thunderbirds-blue-angels.jpg

---

As per the comments below, try this bash script:

declare -A array

for i in *.*; do

    j="${i%-*}.${i##*.}"

    # k="$j"
    # k="${i%-*}-0.${i##*.}"

    for x in "${!array[@]}"; do

        if [[ "$j" == "$x" ]]; then
            k="${i%-*}-${array[$j]}.${i##*.}"
        fi
    done

    (( array["$j"]++ ))

    mv "$i" "$k"
done

Note that you will need to uncomment a value for k depending on how you would like to format the filenames. If you uncomment the first line, only the duplicate basenames will be incremented:

dead-space-album.jpg
dead-space-album-1.jpg
dead-space-album-2.jpg
dead-space-album-3.jpg

If you uncomment the second line, you'll get the following:

alien-skull-0.jpg
alien-skull-1.jpg
alien-skull-2.jpg
alien-skull-3.jpg