cout uint8_t as integers instead of chars

Question

#include
#include
using namespace std;

int main()
{
    cout << (uint8_t)123 << endl;
}

This will out

Answer 1

I definitely do not condone the solution I am about to suggest. I also suspect that it may not be permitted by the standard, but I cannot prove it, as of yet. If someone can provide me a reference that shows that it is not permitted, then I will delete this answer. Anyway, my tests so far indicate that simply overloading the operator in the global scope seems to work.

#include 
#include 

std::ostream & operator<<(std::ostream & os, std::uint8_t val)
{
    return os << static_cast(val);
}

int main()
{
    std::uint8_t val = 123;
    std::cout << val;
}

I wouldn't have thought this would work, but then I realized that the char/unsigned char/signed char overloads for operator<< are all free functions in the std namespace picked up by ADL. And I guess global functions are considered a better match than ADL functions, but I'm not sure about that.