Creating binned histograms in Spark

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夕颜
夕颜 2021-01-07 08:37

Suppose I have a dataframe (df) (Pandas) or RDD (Spark) with the following two columns:

timestamp, data
12345.0    10 
12346.0    12

In Pa

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  •  谎友^
    谎友^ (楼主)
    2021-01-07 09:13

    Here is an answer using RDDs and not dataframes:

    # Generating some data to test with 
    import random
    import datetime
    
    startTS = 12345.0
    array = [(startTS+60*k, random.randrange(10, 20)) for k in range(150)]
    
    # Initializing a RDD
    rdd = sc.parallelize(array)
    
    # I first map the timestamps to datetime objects so I can use the datetime.replace 
    # method to round the times
    formattedRDD = (rdd
                    .map(lambda (ts, data): (datetime.fromtimestamp(int(ts)), data))
                    .cache())
    
    # Putting the minute and second fields to zero in datetime objects is 
    # exactly like rounding per hour. You can then reduceByKey to aggregate bins.
    hourlyRDD = (formattedRDD
                 .map(lambda (time, msg): (time.replace(minute=0, second=0), 1))
                 .reduceByKey(lambda a, b : a + b))
    
    hourlyHisto = hourlyRDD.collect()
    print hourlyHisto
    > [(datetime.datetime(1970, 1, 1, 4, 0), 60), (datetime.datetime(1970, 1, 1, 5, 0), 55), (datetime.datetime(1970, 1, 1, 3, 0), 35)]
    

    In order to do daily aggregates you can use time.date() instead of time.replace(...). Also to bin per hour starting at a not-round date-time object you can increment the original time by the delta to the nearest round hour.

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