Print bash arguments in reverse order

Question

I have to write a script, which will take all arguments and print them in reverse.

I\'ve made a solution, but find it very bad. Do you have a smarter idea?

Answer 1

bash:

#!/bin/bash
for i in "$@"; do
    echo "$i"
done | tac

call this script like:

./reverse 1 2 3 4

it will print:

4
3
2
1