How to pass command line parameters with quotes stored in single variable?

Question

I want to call external application from shell script, but this shell script gets parameters (from other script) in a single variable. All was OK until I did not have to use

Answer 1

This might work, although it's hard to tell without knowing how sh_param handles its arguments.

#!/bin/sh

pass() {
    echo "Result with \"\$@\""
    ./sh_param "$@"
}

pass "single param" separate params