How to pass command line parameters with quotes stored in single variable?

Question

I want to call external application from shell script, but this shell script gets parameters (from other script) in a single variable. All was OK until I did not have to use

Answer 1

Answering my own question. BIG thanks goes to pzanoni. xargs seems to parse correctly anything you are throwing to it :-) "$@", "$", $@ and $ works good with it. So my code now looks like:

#!/bin/sh

pass() {
    echo $* | xargs ./sh_param
}

pass '"single param" separate params'

And result is what I wanted:

Param: single param
Param: separate
Param: params