Python parse int from string

前端 未结 2 1312
误落风尘
误落风尘 2021-01-07 03:33
test1 = \'name1\'
test2 = \'name2\'
..
test3 = \'name45\'
test4 = \'name1231231\'

Let\'s say I have bunch of strings which start with \'name\' and

2条回答
  •  温柔的废话
    2021-01-07 04:06

    If you know that the prefix is name, then you can either remove just that string, or you can skip the first four letters, like so:

    s = 'name123'
    print int(s.replace('name',''))
    
    s = 'name123'
    print int(s[4:])
    

提交回复
热议问题