counting how many time the order of two consecutive number in a file are reversed in a second file in BASH

Question

I got the following problem:

Given 2 files of N numbers like

file1.dat: 1,2,3,4,5,6,7,8,9,0

file2.dat: 2,5,4,7,6,9,8,1,0,3

The file2.dat is a

Answer 1

I know that you already have an accepted clean answer.

Just sharing:

sgeorge-mn:~ sgeorge$ cat stack.sh 
VALUE1=$1
VALUE2=$2
for POS in `sed 's/,/ /g' file1.dat`
do
((COUNT++))
if [[ $VALUE1 == $POS ]] ; then
    VAL1_POS=$COUNT
fi

if [[ $VALUE2 == $POS ]] ; then
        VAL2_POS=$COUNT
fi
done


for MATCH in `sed 's/,/ /g' file2.dat`
do
((COUNT2++))
if [[ $VALUE1 == $MATCH ]] ; then
        VAL1_POS2=$COUNT2
fi
if [[ $VALUE2 == $MATCH ]] ; then
        VAL2_POS2=$COUNT2
fi
done

if [[ $VAL1_POS -gt $VAL2_POS ]] ; then
    P1=1
fi
if [[ $VAL1_POS2 -gt $VAL2_POS2 ]] ; then
    P2=1
fi

if [[ $VAL1_POS -lt $VAL2_POS ]] ; then
    P1=2
fi
if [[ $VAL1_POS2 -lt $VAL2_POS2 ]] ; then
    P2=2
fi

if [[ $VAL1_POS -eq $VAL2_POS ]] ; then
    P1=3
fi
if [[ $VAL1_POS2 -eq $VAL2_POS2 ]] ; then
    P2=3
fi

if [[ $P1 == $P2 ]]; then
    echo "No order change"
else
    echo "Order changed"
fi

How to execute the script:

I am assuming following:

• Both file have exactly same numbers in same order.
• You will not give non existing number (not existing in file*.dat) as input to the script

sgeorge-mn:~ sgeorge$ bash stack.sh 5 7
No order change
sgeorge-mn:~ sgeorge$ bash stack.sh 4 5
Order changed
sgeorge-mn:~ sgeorge$ bash stack.sh 9 0
No order change
sgeorge-mn:~ sgeorge$ bash stack.sh 1 2
Order changed