The logical && and || operators fully evaluate the LHS before doing any evaluation of the RHS.
In the code shown, since ++i is -2, the LHS of the || evaluates to true (1) and the RHS is not evaluated. Therefore, neither j nor k is incremented. The printed result follows: m was assigned 1, i became -2, and j stayed as 2 and k stayed as 0.
The only remaining issue is that && binds tighter than ||, so:
a || b && c
is equivalent to:
a || (b && c)
so if a evaluates to true (non-zero), then neither b nor c is evaluated.
