How to convert string to variable-name in scheme

Question

How can I achieve below in Scheme REPL? Create a variable name from a string.

=>(define (string->variable-name "foo") 12)

=>foo

Answer 1

If what you're passing to string->variable-name is always a string literal (i.e., not a variable that contains a string), you can do that using a syntax-case macro that transforms the string literal to an identifier:

(define-syntax string->variable-name
  (lambda (stx)
    (syntax-case stx ()
      ((_ str)
       (string? (syntax->datum #'str))
       (datum->syntax #'str (string->symbol (syntax->datum #'str)))))))

and conversely, a variable-name->string macro could look like this:

(define-syntax variable-name->string
  (lambda (stx)
    (syntax-case stx ()
      ((_ id)
       (identifier? #'id)
       (datum->syntax #'id (symbol->string (syntax->datum #'id)))))))

However, remember: this will only work if you are working with string (in case of string->variable-name) or identifier (in case of variable-name->string) literals.

---

If, on the other hand, you want the ability to reflect on names in your current Scheme environment, this is not supported by standard Scheme. Some implementations, like Guile or Racket, do have this capability.

Here's a Guile example:

> (module-define! (current-module) 'foo 12)
> foo
12
> (define varname 'bar)
> (module-define! (current-module) varname 42)
> bar
42

and a Racket example:

> (namespace-set-variable-value! 'foo 12)
> foo
12
> (define varname 'bar)
> (namespace-set-variable-value! varname 42)
> bar
42