Converting number to byte array

Question

Hi I have a base 10 number for example 3198, and the hex representation is 0x0C7E

How do I convert that number to hex and put that hex value in a byte array in the f

Answer 1

#include 

union uint32_value {
    unsigned int value;

    struct little_endian {
        unsigned char fou;
        unsigned char thi;
        unsigned char sec;
        unsigned char fir;
    } le;

    struct big_endian {
        unsigned char fir;
        unsigned char sec;
        unsigned char thi;
        unsigned char fou;
    } be;
};

int main(void)
{
    union uint32_value foo;
    foo.value = 3198;
    printf("%02x %02x %02x %02x\n", foo.le.fir, foo.le.sec, foo.le.thi, foo.le.fou);

    return 0;
}