Converting number to byte array

Question

Hi I have a base 10 number for example 3198, and the hex representation is 0x0C7E

How do I convert that number to hex and put that hex value in a byte array in the f

Answer 1

Maybe this will work ?

uint32_t x = 0x0C7E;
uint8_t bytes[3];

bytes[0] = (x >> 0)  & 0xFF;
bytes[1] = (x >> 8)  & 0xFF;
bytes[2] = (x >> 16) & 0xFF;


/* Go back. */
x = (bytes[2] << 16) | (bytes[1] << 8) | (bytes[0] << 0);