Why this union's size is 2 with bitfields?

Question

I am working on turbo C on windows where char takes one byte.Now my problem is with the below union.

union a
{
 unsigned char c:2;
}b;
void main()
{
printf(\         


        

Answer 1

Turbo C is based on 8086 microprocessor which has two byte word boundary. The atomic reading and writing is typically bound to CPU's architecture, so the compiler is adding some slack bytes to align your data structure.

Calling #pragma pack(1) may be able to disable it, but not sure if it works on Turbo C.