As I am rather new to R, I am trying to learn how I can extract two values from a XML file and loop over 5603 other (small, <2kb) XML files in my working directory.
Slightly different approach to Richard's (only slightly). Used ldply to make a data frame before writing it out to a file. You should select his for the answer since the "guts" of the ldply function is his, but this just shows an alternate way of doing it (assuming you want one file vs many files):
setwd("LOCATION_OF_XML_FILES")
xmlfiles <- list.files(pattern = "*.xml")
dat <- ldply(seq(xmlfiles), function(i){
doc <- xmlTreeParse(xmlfiles[i], useInternal = TRUE)
zipcode <- xmlValue(doc[["//ZipCode"]])
amount <- xmlValue(doc[["//AwardAmount"]])
return(data.frame(zip = zipcode, amount = amount))
})
head(dat)
## zip amount
## 1 442420001 45000
## 2 479072114 400580
## 3 303320420 22050
## 4 326112002 12000
## 5 265066845 37000
## 6 168027000 300000
write.csv(dat, "zipamount.csv", row.names=FALSE)
You could use append=TRUE with Richard's approach and use a single file name in that write.table to do the same thing. You can also tweak the output settings of write.csv (or write.table) to get the output format you eventually want to work with.
You can also add recursive = TRUE to the list.files to go through all the subdirectories vs put all ~5,600 files into one directory (that can have performance issues on some filesystems/operating systems).