Simple Character Interpretation In C

Question

Here is my code

 #include

 void main()
 {
     char ch = 129;
     printf(\"%d\", ch);
 }

I get the output as -127. What d

Answer 1

Your char is most likely an 8-bit signed integer that is stored using Two's complement. Such a variable can only represent numbers between -128 and 127. If you do "127+1" it wraps around to -128. So 129 is equivalent to -127.