Simple Character Interpretation In C

Question

Here is my code

 #include

 void main()
 {
     char ch = 129;
     printf(\"%d\", ch);
 }

I get the output as -127. What d

Answer 1

It means you ran into undefined behavior.

Any outcome is possible.

char ch=129; is UB because 129 is not a representable value for a char for you specific setup.