bash: How do I ensure termination of process substitution used with exec?

Question

If I run

$#/bin/bash
for i in `seq 5`; do
    exec 3> >(sed -e \"s/^/$i: /\"; echo \"$i-\")
    echo foo >&3
    echo bar >&3
    exec 3&         


        

Answer 1

The "obvious" answer is to get rid of the process substitution.

for i in `seq 5`; do
    echo foo | sed -e "s/^/$i: /"; echo "$i-"
    echo bar | sed -e "s/^/$i: /"; echo "$i-"
done

So the question becomes, do you really need to structure your code using process substitution? The above is much simpler than trying to synchronize an asynchronous construct.