At the top of my UITableViewController is the following:
let queue = DispatchQueue(label: \"background\")
When a task is dele
We need to understand the fact Realm Objects cannot be accessed from different threads. What does this means and how to workout this issue.
First, realm objects cannot be access from different thread means, one instance of Realm defined in one thread cannot be access from different thread. What we should do actually is we need to have different instance of realm instance for each thread.
For eg. let's look at following e.g. where we insert 50 records in database asynchronously in background thread upon button click and we add notification block in main thread to update the no of people in count label. Each thread (main and background ) have its own instance of realm object to access Realm Database. Because Realm Database achieves thread safety by making instances of Realm thread-confined.
class Person: Object {
dynamic var name = ""
convenience init(_ name: String) {
self.init()
self.name = name
}
}
override func viewDidAppear(_ animated: Bool) {
let realmMain = try! Realm ()
self.people = realmMain.objects(Person.self)
self.notification = self.people?.addNotificationBlock{ [weak self] changes in
print("UI update needed")
guard let countLabel = self?.countLabel else {
return
}
countLabel.text = "Total People: \(String(describing: self?.people?.count))"
}
}
@IBAction func addHandler(_ sender: Any) {
print(#function)
let backgroundQueue = DispatchQueue(label: "com.app.queue",
qos: .background,
target: nil)
backgroundQueue.async {
print("Dispatched to background queue")
let realm = try! Realm()
try! realm.write {
for i in 1..<50 {
let name = String(format: "rajan-%d", i)
//print(#function, name)
realm.add(Person(name))
}
}
}
}