how to get second highest salary department wise without using analytical functions?

Question

Suppose we have 3 employees in each department.we have total 3 departments . Below is the sample source table

Emp deptno salary
A    10     1000
B    10              


        

Answer 1

It is a pain, but you can do it. The following query gets the second highest salary:

select t.deptno, max(t.salary) as maxs
from table t
where t.salary < (select max(salary)
                  from table t2
                  where t2.deptno = t.deptno
                 )
group by t.deptno;

You can then use this to get the employee:

select t.*
from table t join
     (select t.deptno, max(t.salary) as maxs
      from table t
      where t.salary < (select max(salary)
                        from table t2
                        where t2.deptno = t.deptno
                       )
      group by t.deptno
     ) tt
     on t.deptno = tt.deptno and t.salary = tt.maxs;