How to exclude a single file from package with setuptools and setup.py

Question

I am working on blowdrycss. The repository is here.

I want the settings file for blowdrycss_settings.py to be excluded from the final pack

Answer 1

Imagine you have a project

root
├── setup.py
└── spam
    ├── __init__.py
    ├── bacon.py
    └── eggs.py

and you want to exclude spam/eggs.py from packaging:

import fnmatch
from setuptools import find_packages, setup
from setuptools.command.build_py import build_py as build_py_orig


excluded = ['spam/eggs.py']


class build_py(build_py_orig):
    def find_package_modules(self, package, package_dir):
        modules = super().find_package_modules(package, package_dir)
        return [
            (pkg, mod, file)
            for (pkg, mod, file) in modules
            if not any(fnmatch.fnmatchcase(file, pat=pattern) for pattern in excluded)
        ]


setup(
    packages=find_packages(),
    cmdclass={'build_py': build_py}
)

Globs and multiple entries in excluded list will work too because it is consumed by fnmatch, so you can e.g. declare

excluded = [
    'modules_in_directory/*.py',
    'modules_in_subtree/**/*.py',
    'path/to/other/module.py'
]

etc.

This recipe is based on my other answer to the question setup.py exclude some python files from bdist . The difference is that this recipe excludes modules based on file globs, while the other one excludes modules based on qualnames, for example

excluded = ['spam.*', '*.settings']

will exclude all submodules of spam package and all modules named settings in every package and subpackage etc.