Find specific pattern and print complete text block using awk or sed

Question

How can find a specific number in a text block and print the complete text block beginning with the key word \"BEGIN\" and ending with \"

Answer 1

This might work for you (GNU sed):

sed -n '/^BEGIN/{x;d};H;/^END/{x;s/^B: 567/&/mp}' file

or this:

sed -n '/^BEGIN/!b;:a;$!{N;/\nEND/!ba};/\nB: 567/p' file