Give such a data frame df:
id_ val
11111 12
12003 22
88763 19
43721 77
...
I wish to add a column
Recursive functions are not easily vectorisable. However, you can optimize your algorithm with numba. This should be preferable to a regular loop.
from numba import jit
@jit(nopython=True)
def foo(val):
diff = np.zeros(val.shape)
diff[0] = val[0] * 0.4
for i in range(1, diff.shape[0]):
diff[i] = (val[i] - diff[i-1]) * 0.4 + diff[i-1]
return diff
df['diff'] = foo(df['val'].values)
print(df)
id_ val diff
0 11111 12 4.8000
1 12003 22 11.6800
2 88763 19 14.6080
3 43721 77 39.5648