Why are field initializers of a derived class are executed before base classes's initializers

Question

constructors are executed in the order from top to bottom I.E. base\'s first followed by derived one. This arangement is based on an important OOP assurance that an object (

Answer 1

Why are field initializers of a derived class executed before the base class field initializers?

Good question. I answered your question in these blog posts from 2008:

https://docs.microsoft.com/en-us/archive/blogs/ericlippert/why-do-initializers-run-in-the-opposite-order-as-constructors-part-one

https://docs.microsoft.com/en-us/archive/blogs/ericlippert/why-do-initializers-run-in-the-opposite-order-as-constructors-part-two