Generating random numbers on open-open interval (0,1) efficiently

Question

I\'m looking for an efficient way to generate random floating-point numbers on the open-open interval (0,1). I currently have an RNG that generates random integers on the cl

Answer 1

You are already there.

The smallest distance between two floats your current generator produces is 1/(2^32).

So, your generator is efectively producing [0,1-1/(2^32)].

1/(2^32) is greater than FLT_MIN.

Thus if you add FLT_MIN to your generator,

float open_open_flt = FLT_MIN + closed_open_flt;

you'll get [FLT_MIN,1-(1/(2^32))+FLT_MIN], which works as a (0,1) generator.