How do I launch multiple batch files from one batch file with dependency?

Question

I want to run one batch file, that start the other batch files. I looked at a similar question posted here: How to run multiple .BAT files within a .BAT file

I follo

Answer 1

Answer:

Add the /wait option to the start command.

WAIT        Start application and wait for it to terminate.

Example:

start /wait cmd /k CALL D:\jboss-5.1.0.GA-jdk6\jboss-5.1.0.GA\bin\run.bat

start /wait cmd /k CALL batch1.bat

start /wait cmd /k CALL batch2.bat

start /wait cmd /k CALL batch3.bat

Otherwise just use a ping delay between the starts. (See user706837's Answer)

References:

Technet, Rob, SS64, DosTips