Find longest occurrence of same number in array

Question

Using JavaScript, I\'m trying to find a way to find the longest occurrence of the same number (in this case, 1) in an array.

For instance, here\'s a sample array:

Answer 1

Unfortunatly, a question has been marked as duplicate, but it was not the same as this one. So I must put my answer here, sorry…

let tab = [0,0,0,1,1,1,0,0,0,0,1,0,1,1,1,1,1]
  , arr = []
  , n = 0
  , res = null ;

for(let i of tab)
{
    if ( i ) { ++ n }
    else if ( n ) { arr.push(n) ; n = 0 }
}
arr.push(n) ;

res = Math.max(...arr);

console.log("Streak with 1 is ", Math.max(...arr));

It's a better solution than with reduce, slower, as you can see:

let tab = [0,0,0,1,1,1,0,0,0,0,1,0,1,1,1,1,1];
let arr = [];
let n = 0;
let res = null;

let loop = 0;
let start = new Date().getTime();

while (loop < 1000000){
  ++ loop;
  
  arr = [];
  for(let i of tab)
  {
      if ( i ) { ++ n }
      else if ( n ) { arr.push(n) ; n = 0 }
  }
  arr.push(n);
  res = Math.max(...arr);
}
let end = new Date().getTime();
console.log("laps old fashion = ", end - start);

loop = 0;
let streaks = null;
start = new Date().getTime();
while (loop < 1000000){
  ++ loop;
  streaks = tab.reduce((res, n) => 
    (n ? res[res.length-1]++ : res.push(0), res)
  , [0]);
  res = Math.max(...streaks);
}
end = new Date().getTime();
console.log("laps reduce = ", end - start);

console.log("Streak with 1 is ", Math.max(...arr));