How to convert an alphanumeric phone number to digits

Question

UPDATE:

The final version of my utility looks like this:

StringBuilder b = new StringBuilder();

for(char c : inLetters.toLowerCase(         


        

Answer 1

If you want a solution that doesn't force you to enumerate all of the letters, you could do something like:

char convertedChar = c;
if (Character.isLetter(c)) {
    //lowercase alphabet ASCII codes: 97 (a)-122 (z)
    int charIndex = ((int)c) - 97;
    //make adjustments to account for 's' and 'z'
    if (charIndex >= 115) { //'s'
        charIndex--;
    }
    if (charIndex == 121) { //'z'-1
        charIndex--;
    }
    convertedChar = (char)(2 + (charIndex/3));
}
result += convertedChar;