Counting digits using while loop

Question

I was recently making a program which needed to check the number of digits in a number inputted by the user. As a result I made the following code:

int x;            


        

Answer 1

In your particular example you could read the number as a string and count the number of characters.

But for the general case, you can do it your way or you can use a base-10 logarithm.

Here is the logarithm example:

#include 
#include 

using namespace std;

int main()
{
    double n;
    cout << "Enter a number: ";
    cin >> n;

    cout << "Log 10 is " << log10(n) << endl;
    cout << "Digits are " << ceil(log10(fabs(n)+1)) << endl;
    return 0;
}