How to continue with next line in a Python's try block?

Question

e.g.

try:
    foo()
    bar()
except: 
    pass

When foo function raise an exception, how to skip to the next line (bar) and execute it?

Answer 1

If you have just two functions, foo() bar(), check the other solutions. If you need to run A LOT of lines, try something like this example:

def foo():
    raise Exception('foo_message')
def bar():
    print'bar is ok'
def foobar():
    raise  Exception('foobar_message')

functions_to_run = [
     foo,
     bar,
     foobar,
]

for f in functions_to_run:
    try:
        f()
    except Exception as e:
        print '[Warning] in [{}]: [{}]'.format(f.__name__,e)

Result:

[Warning] in [foo]: [foo_message]
bar is ok
[Warning] in [foobar]: [foobar_message]