Is it possible to make an object expose the interface of an type parameter?

Question

In C#, is it possible to write something like this:

public class MyClass : T 
    where T : class, new() 
{
}

I know that the abov

Answer 1

You could have a look at DynamicObject and do something like this:

class Foo : DynamicObject
{
    private T _instance;
    public Foo(T instance)
    {
        _instance = instance;
    }
    public override bool TrySetMember(SetMemberBinder binder, object value)
    {
        var member = typeof(T).GetProperty(binder.Name);
        if (_instance != null &&
            member.CanWrite &&
            value.GetType() == member.PropertyType)
        {
            member.SetValue(_instance, value, null);
            return true;
        }
        return false;
    }

    public override bool TryGetMember(GetMemberBinder binder, out object result)
    {
        var member = typeof(T).GetProperty(binder.Name);
        if (_instance != null &&
            member.CanRead)
        {
            result = member.GetValue(_instance, null);
            return true;
        }
        result = null;
        return false;
    }
}

class Bar
{
    public int SomeProperty { get; set; }
}

class Program
{
    static void Main(string[] args)
    {
        var bar = new Bar();
        dynamic thing = new Foo(bar);
        thing.SomeProperty = 42;
        Console.WriteLine(thing.SomeProperty);
        Console.ReadLine();
    }
}