Why I get; initializing 'char *' with an expression of type 'const char *' discards qualifiers?

Question

I can\'t figure out why I get this warning from clang by myself:

function_prototype_const_modifier.c:13:8: warning: initializing \'char *\' with         


        

Answer 1

You just need to change:

char *ptr1 = source;

to:

const char *ptr1 = source;